find the angle between force=3i+4j and displacement=5i+4j+3k
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We can solve it using dot product.
F.S = |F|×|S|×cos∆
(3i+4j+0k).(5i+4j+3k) = 25 × 5√2× cos∆
15+16+0= 125√2×cos∆
31=125√2×cos∆
cos∆=31/(125√2)
∆= cos(inverse)(31/125√2)
F.S = |F|×|S|×cos∆
(3i+4j+0k).(5i+4j+3k) = 25 × 5√2× cos∆
15+16+0= 125√2×cos∆
31=125√2×cos∆
cos∆=31/(125√2)
∆= cos(inverse)(31/125√2)
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