find the angle between radius vector and tangent r=a(1+sinθ)
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Ф = π/4 + Θ/2 is the correct answer
Given:
r = a(1+ sinΘ)
To find:
the angle between radius vector and tangent r=a(1+sinθ)
solution:
r=a(1+sinθ)
(1/r)dr/dΘ = cosΘ/(1+sinΘ)
rdΘ/dr = 1 + sinΘ/ cosΘ
tanΨ = (cos²Θ/2 + sin²Θ/2 + 2sinΘ/2 . cosΘ/2)/ (cos²Θ/2 - sin²Θ/2)
= (cosΘ/2 + sinΘ/2)²/((cosΘ/2 - sinΘ/2) . (cosΘ/2 + sinΘ/2))
= 1 + tanΘ/2 / 1 - tanΘ/2
= tan( π/4 + Θ/2)
hence, Ψ = π/4 + Θ/2 is the correct answer
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