Find the angle between square root 3x+y=1 and x+square root 3y=1
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tan theeta =m2-m1/1-m2m1
sq root 3x+y=1
m=-sq root 3
x+sq root 3y=1
m=-1/sq root 3
by taking m1=sq root -3
&m2=-1/sq root 3
tan theeta =30
sq root 3x+y=1
m=-sq root 3
x+sq root 3y=1
m=-1/sq root 3
by taking m1=sq root -3
&m2=-1/sq root 3
tan theeta =30
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