Question

find the angle between the curves x2=2(you+1) ; y=8/x2+4​

Answer 1

Answer:

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xy=4 ...(1)

x

2

+y

2

=8 ...(2)

∴ Put y=

x

4

in equation (2)

x

2

+

x

2

16

=8

So, now

x=y=2

& x=y=−2

These two equation intersect at two points (2,2)&(−2,−2)

Now,

dx

dy

)

(−2,−2)

=x

dx

dy

+y=0

So, Let (s

1

)=

dx

dy

=−

x

y

=−1(for(−2,−2))

Again,

dx

dy

)

(−2,−2)

=2x+2y

dx

dy

=0

=x+y

dx

dy

=0

So, Let (s

2

)=

dx

dy

=−

y

x

=−1(for(−2,−2))

Now, tanθ=

∣

∣

∣

∣

∣

1+s

1

×s

2

s

1

−s

2

∣

∣

∣

∣

∣

Since s

1

=s

2

they cut at 0 angle

Step-by-step explanation:

I hope this answer will help you