Find the angle between the hours and minute hand at 7:20 pm.... its not that easy it looks
Yuviman:
6:30 pm 90 degree then 7:20pm this time same that degree
Answers
Answered by
68
Heya!!Here is your answer friend ⤵⤵
↔↔↔↔↔↔↔↔↔↔↔↔↔↔↔
⏪The formula for calculating the angle is ,
So , the angle formed is 100 degrees .
Hope it helps you ✌✌
↔↔↔↔↔↔↔↔↔↔↔↔↔↔↔
⏪The formula for calculating the angle is ,
So , the angle formed is 100 degrees .
Hope it helps you ✌✌
Answered by
27
At exactly 7:00 be our reference. Let's start our observation here - Start time and start position.
Minute hand — 0 deg.
Hour hand — 210 deg.
By 7:20, the minute hand is 120 degs ahead from its start position -
Minute hand — 0 + 120 degs
In this duration, hour hand had moved some angle ahead, say x degs.
Hour hand — 210 + x degs
Then the angle between minute and hour hand becomes -
(210 + x) - (0 + 120) = 90 + x
So if we find x, we get the answer. x is the angle moved by hour hand in 20 mins. In 60 mins, hour hand moves by 30 degs, so in 20 mins it must move by 20*(30/60) = 10 degs. So x = 10
Therefore the required angle is 90 + 10 = 100 degs.
This can be solved faster if we consider relative speed of min hand compared to second hand.
Minute hand — 0 deg.
Hour hand — 210 deg.
By 7:20, the minute hand is 120 degs ahead from its start position -
Minute hand — 0 + 120 degs
In this duration, hour hand had moved some angle ahead, say x degs.
Hour hand — 210 + x degs
Then the angle between minute and hour hand becomes -
(210 + x) - (0 + 120) = 90 + x
So if we find x, we get the answer. x is the angle moved by hour hand in 20 mins. In 60 mins, hour hand moves by 30 degs, so in 20 mins it must move by 20*(30/60) = 10 degs. So x = 10
Therefore the required angle is 90 + 10 = 100 degs.
This can be solved faster if we consider relative speed of min hand compared to second hand.
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