Question

find the angle between the line x+1=0 and√3x+y​

Answer 1

Answer:

ANSWER

When written in form y=mx+c, m= slope of line

For L

1

: y=−

3

x−1=m

1

=−

3

For L

2

:o.y=x+1⇒y=

0

x

+

0

1

⇒m

2

→∞

Slope between lines =

∣

∣

∣

∣

∣

1+m

1

m

2

m

2

−m

1

∣

∣

∣

∣

∣

=tanθ

θ=Angle ⇒θ=tan

−1

⎝

⎜

⎜

⎛

∣

∣

∣

∣

∣

∣

∣

∣

m

1

+

m

2

1

1−

m

2

m

1

∣

∣

∣

∣

∣

∣

∣

∣

⎠

⎟

⎟

⎞

=tan

−1

(

∣

∣

∣

∣

∣

m

1

1

∣

∣

∣

∣

∣

)=tan

−1

(

∣

∣

∣

∣

∣

3

1

∣

∣

∣

∣

∣

)

⇒−θ=150

o

or 30

o

.

solution

Answer 2

$\sf{ \purple{Answer \: in \: Attachment}}$

Hope this helps you mate✌