Question

find the angle between the lines ab and bc where A.(0,0) B.(√3,3) C.(-√3,3)​

Answer 1

Answer:

Let,

A(0,0)

B(√3,3)

C(-√3,3)

Now,

Distance between AB-----

AB=√(√3-0)²+(3-0)²

AB=√3+9

AB=✓12

AB=√4*3

AB=2√3 units

again,

BC=√(-√3-√3)²+(3-3)²

BC=√6+0

BC=√6 units

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###Hope it will help you###!