Find the angle between the lines of intersection of the plane x-3y+z=0and the cone x2-5y2+Z2=0
Answers
Answered by
1
Answer:
The angle between the lines of intersection of the plane x-3y + z = 0 and a quadric cone x^2 - 5y^2 + 2 = 0 is 360⁰
Step-by-step explanation:
Similar questions