Find the angle between the lines x/1=y/2 =z/3 and (x+1)/2=(y-3)/-7=(z+2)/7
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Given lines are
1
x−7
=
−5
y+3
=
3
z
...(i)
and
−7
2−x
=
2
y
=
1
z+5
⇒
7
x−2
=
2
y
=
1
z+5
...(ii)
DR's of line equations (i) and (ii) are
(a
1
,b
1
,c
1
)=(1,−5,3)
and (a
2
,b
2
,c
2
)=(7,2,1)
Therefore, cosθ=
a
1
2
+b
1
2
+c
1
2
a
2
2
+b
2
2
+c
2
2
a
1
a
2
+b
1
b
2
+c
1
c
2
=
1
2
+(−5)
2
+(3)
2
(7)
2
+(2)
2
+(1)
2
1×7+(−5)×2+3×1
=
1+25+9
49+4+1
7−10+3
=0
⇒θ=
2
π
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