Math, asked by Remin7097, 9 months ago

Find the angle between the lines x+2y+13=0 and 2x-y+7=0 is

Answers

Answered by MaheswariS
1

\textbf{Given:}

\textsf{Lines are}

\mathsf{x+2y+13=0\;and\;2x-y+7=0}

\textbf{To find:}

\textsf{The angle between the given lines}

\textbf{Solution:}

\mathsf{Slope\;of\;x+2y+13=0\;is\;m_1=\dfrac{-1}{2}}

\mathsf{Slope\;of\;2x-y+7=0\;is\;m_2=\dfrac{-2}{-1}=2}

\mathsf{Now,}

\mathsf{m_1{\times}m_2}

\mathsf{=\dfrac{-1}{2}{\times}2}

\mathsf{=-1}

\implies\textsf{Product of slope is -1}

\therefore\textsf{The given two lines are perpendicular}

\mathsf{Hence,\;angle\;between\;the\;lines\;is\;90^\circ}

\textbf{Find more:}

The angle between the lines ,2x+3y=5 and 3x-2y=7

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The angle between the line 2x+y+1=0 and x+ky+5=0 is 90° then k=

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