Question

find the angle between the lines x+2y+3=0 and 2x-3y+4=0​

Answer 1

Step-by-step explanation:

for the line x+2y+3=0

slope(m1)=-1/2

for line 2x-3y+4=0

slope(m2)=2/3

tanθ=|m1-m2l1+m1.m2|

tanθ=-1/2-2/3/1-1/3

θ=tan-1(7/4)