Question

find the angle between the lines y = 3x + 7 and 3y - x = 8​

Answer 1

Step-by-step explanation:

3x+y−7=0 and -x+3y-8=0

write in the form y=mx+c

i.e.y=−3x+7, y= (x+8)/3

∴m1=−3 and m2= 1/3

tan(A−B)= 1+tanAtanB / tanA−tanB

tan(A-B) =(1 -3×1/3)/3-1/3

= 0

∴ Angle b/w then is = 0⁰