Question

Find the angle between the pair of straight lines x+√3y-8=0 and x-√3y+2=0

Answer 1

Answer:

angle= 120°

Step-by-step explanation:

slope of first line = -1/√3

so, angle=150°. in anticlockwise direction from X axis

slope of 2nd line=1/√3

so, anlge =30°. in anticlockwise direction from X axis

angle between them=120°