Question

Find the angle between the planes x+y-5z+6=0,2x+3y+6z+5=0

Answer 1

P1:2x−3y−6z=5P2:6x+2y−9z=4

Angle between plane is angle between normals.

∴cosθ=22+32+6262+22+922×6+(−3)×2+(−6)(−9)=7760

θ=cos−1(7760)

Hope this method helps.

Answer 2

Answer:

Step-by-step explanation: