find the angle between the radius vector and the tangent of the following curves 2a/r=1-cosx
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0 /2 is correct I think so
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Step-by-step explanation:
The radius is given by r = a (1−cosθ).
In the Cartesian coordinate system, x=rcosθ and y=rsinθ.
x=a(1−cosθ)cosθ=a(cosθ−cos2θ), and,
y=a(1−cosθ)sinθ=a(sinθ−cosθsinθ)=a(sinθ−sin2θ2)
dxdθ=a(−sinθ+2cosθsinθ)=−a(sinθ−sin2θ), and,
dydθ=a(cosθ−cos2θ).
The slope of the tangent to the curve is,
d y dx=cosθ−cos2θsinθ−sin2θ=m1.
The slope of the radius vector is m2=tanθ=sinθcosθ.
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