Question

Find the angle between the straight lines 2x-8y=7 and 6x-y=12​

Answer 1

Answer:

hope it may help u

please mark it as a brainlist answer

Answer 2

The given question we have to find the angle between the straight lines.

The equation of the lines are 2x-8y=7 and 6x-y=12

The formula for the slope is

$y = mx + c$

The slope of the first equation is

$2x - 8y = 7 \\ 2x - 7 = 8y \\ \frac{2x}{8} - \frac{7}{8} = y$

$m1 = \frac{2}{8} = \frac{1}{4}$

The slope of the second equation is

$6x - y = 12 \\ 6x - 12 = y$

The angle tan theta =

$tan \: theta = | \frac{m1 - m2}{1 + m1m2} | \\ | \frac{ \frac{1}{4} - 6 }{1 + \frac{1}{4} \times 6 } | \\ | \frac{ \frac{1 - 24}{4} }{1 + \frac{3}{2} } | \\ | \frac{ \frac{ - 23}{4} }{ \frac{2 + 3}{2} } | \\ | \frac{ \frac{ - 23}{4} }{ \frac{5}{2} } | \\ | \frac{ - 23}{4} \times \frac{2}{5} | \\ | \frac{ - 23}{10} | \\ = \frac{ + 23}{10}$

Hence, therefore the final answer is

$\frac{ + 23}{10}$

theta = tan -1 (23/10)

# spj2

we can find the similar questions through link given below

https://brainly.in/question/16949506?referrer=searchResults