Question

find the angle between the vector 4i+3j-4k and 3i +4k+6j
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Answer 1

Answer:

90 degrees

Explanation:

apply ab cos theeta =a dot b

(root 16+9+16 )(root 9+16+36) cos theeta =4*3+3*4-4*6

cos theeta=12+12-24/(root 16+9+16 )(root 9+16+36)

cos theeta =0

thus theeta =90

with best wishes