Math, asked by dennischeruiyot, 1 year ago

find the angle between the vectors 2i+6j+3k and 12i-4j+3k

Answers

Answered by kirannaidu137

9

costetha=(2*12-6*4+9)/√4+36+9√144+16+9
costheta=9/7*13
angle=cosinverse(9/7*13)

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