Find the angle between the vectors A = i + 2j - k and B = 2i- 3j + 6k
Answers
Answered by
5
Answer:
Given vectors are
A=2i+3j+k and B=-3i+6k.
Cosine of angle θ between vectors A and B is given by
cosθ=(A.B)/(|A||B|)
Calculate A.B as
A.B=(2i+3j+k).(-3i+6k)
=-6(i.i)+12(i.k)-9(j.i)+18(j.k)-3(k.i)+
6(k.k)
=-6+0-0+0-0+6
=-6+6=0
Thus cosθ=0=>θ=90°.
Hence given vectors are orthogonal to each other (angle between them is 90°).
Hope you got your point......
Answered by
2
Answer:
you can use the formula
cos theta= a.b/|a||b|
= -10/√6×7
= -10/7√6
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