Find the angle between the vectors A = î + 2j-k, B = -î + j^ - 2k
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Answered by
2
Answer:
Pi/3
Explanation:
A.B=ABcostheta
A. B=3
Take magiltude of a and b = root6 and root6 respectively then
A. B/AB= cos theta
=1/2
=cos(pi/3)
Answered by
10
Explanation:
hence,cos theta=1/2 and then theta i.e. angle between the vector is 60°
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