Find the angle between the vectors a=i+j+k and b=-i-j+2k
Answers
Answered by
17
Explanation:
Here a.b=(-1*1)+(-1*1)+(2*1)
i.e a.b=0
Now
a.b=|a|.|b| cosα
Cosα=0
α=90°
I think this is the answer....
Answered by
2
Use,
a.b= |a| |b| cos theta
Cos theta= a.b/|a| |b|
Then find the dot product and the magnitude of the vectors
The answer will be 90 degrees
a.b= |a| |b| cos theta
Cos theta= a.b/|a| |b|
Then find the dot product and the magnitude of the vectors
The answer will be 90 degrees
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