Find the angle between the vectors A vector = 2 icap +4 jcap +6 kcap and B vector = 3 icap + j cap +2 kcap
THIS QUESTION IS 11 STANDARD QUESTION.
Please please please please help me.
Answers
Answered by
84
''Now, For finding the angle, we usually use Dot product since it is easier than Cross product.''
Now, for magnitude of Vector A and Vector B.
Now, Using the formula of Dot Product,
where α is the angle between Vector A and B.
∴
∴ 22 = 2 × 14 × Cosα
∴ Cosα = 11/14
∴ α = Cos⁻¹(11/14)
Hope it helps.
Answered by
9
Answer:
Let θ ( = 120°) be the angle between the two vectors P and Q.
|R|² = |P|² + |Q|² + 2|P||Q|Cosθ
∴ |R|² = P² + Q² + 2PQ × -1/2
∴ R² = P² + Q² - PQ
Also, Let Resultant makes an angle α ( = 90) with smaller one.
Then,
Q = -PCosθ
∴ Q = -PCos120
∴ Q = -P × - 1/2
∴ Q = P/2
∴ Q = 40/2 [Since, P = 40].
∴ Q = 20 N.
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