Question

Find the angle between two equal forces of magnitude 300N each, if their resultant is 150N find the angle between them ​

Answer 1

Answer:

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Explanation:

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Answer 2

Answer:

The angle between both the forces is $\theta=151.04^{0}$

Explanation:

Given that,

The resultant of two forces of magnitude 300N is 150N.

We are required to find the angle between the forces.

Let us write the given data in symbolic form as shown below

$F_{1}=F_{2}=300N\\R=150N$

Let the angle between the two forces be $\theta$.Therefore,

According to parallelogram law of vectors,the resultant of two vectors is

$R=\sqrt{P^{2}+Q^{2}+2PQcos\theta}$

Substituting the given values in above relation,we get

$150=\sqrt{300^{2}+300^{2}+2(300)(300)cos\theta} \\= > 150^{2}=90000+90000+2(90000)cos\theta\\= > -157500=180000cos\theta\\= > cos\theta=-0.875\\= > \theta=cos^{-1}(-0.875)=151.04^{0}$

Therefore,the angle between both the forces is $\theta=151.04^{0}$

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