find the angle between two forces of equal magnitude when the magnitude of the resultant is also equal to the magnitude of either of these forces
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1
Answer:
see attachment its clear. btw ur quadrants are wrong, its all positive in 1st
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3
Answer:
angle is 120 degree
Explanation:
Let the Magnitude of each force be F
So,
According to the question,
Fr = Resultant
F= (F^2 + F^2 +2*F*Fcosθ)^0.5
Squaring both sides,
F^2 = F^2 + F^2 +2*F*Fcosθ
F^2 = F^2 (1 + 1 +2cosθ)
1 = 2(1+cosθ)
0.5 = (1+cosθ)
cosθ = -0.5
So, θ = 120
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