Question

find the angle between two vector A= 2i-j-3k and b = i+2j-3k
plzzz help me​

Answer 1

Explanation:

A= 2i-j-3k

B= i+2j-3k

|A|= √ 2² +1²+3²= √14

|B|= √ 1²+2²+3² = √14

apply

cos theta = A.B / |A| |B|

to get your answer...