Find the angle between two vector 'a' and vector 'b' with magnitude √3 and 2 respectively having vector 'a'. Vector 'b'= √6
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If α is the angle between the vectors, then
cos α = a.b / |a| |b| = √6 / (√3 x 2) = √2 / 2 = 1/√2
So, α = 45°
cos α = a.b / |a| |b| = √6 / (√3 x 2) = √2 / 2 = 1/√2
So, α = 45°
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