Find the angle between two vectors a and b if a=i+2j+3k and b=2i-j
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Answer:
the angle between two vectors are 90°
Step-by-step explanation:
formula for angle between two vector is
cos∅ = a.b /|a| |b|
given, a = i + 2j + 3k , b = 2i - j
property of dot product
i.i = j.j = k.k = 1
i.j = j.k = k.i = 0
dot product of a & b is
a.b = (i + 2j + 3k).(2i - j)
a.b = 2 - 2 = 0
and
|a| = √(1² + 2² + 3²) = √14
|b| = √{2² + (-1)²} = √5
cos∅ = a.b/|a| |b|
cos∅ = 0/√14 √5
cos∅ = 0
cos∅ = cos90
∅ = 90°
thanks,
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