Question

find the angle between two vectors where a vector = 2i^+j^-k^ ,b vector =j^-k^
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Answer 1

$\sf{\bold{\pink{\underline{\underline{Given}}}}}$

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Half the perimeter of rectangular garden is 36m ; Perimeter = 36 × 2 = 72cm

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Length is 4m more than width.

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$\sf{\bold{\green{\underline{\underline{To\: find}}}}}$

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Length and breadth of the garden = ??

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$\sf{\bold{\green{\underline{\underline{Solution}}}}}$

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let the width be x

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Therefore ;

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length = width + 4

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length = x + 4

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$\sf{\red{\boxed{\bold{perimeter = 2 ( length + breadth ) }}}}$

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72 = 2 ( x + 4 + x )

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72 = 2 ( 2x + 4 )

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72 = 4x + 8

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4x = 72 - 8

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4x = 64

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x = 64 / 4

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x = 32 / 2

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x = 16

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putting value of x in length and breadth

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width = x = 16m

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length = x + 4 = 16 + 4 = 20m

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$\sf{\bold{\green{\underline{\underline{Answer}}}}}$

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Length of the field = 20m

Breadth of the field = 16m

Answer 2

Answer:

2i^+j^-k^ ,b vector =j^-k^=vector