Question

find the angle between vector whose direction ratio are proportional to2,3,-6and 3,-45​

Answer 1

Answer:

ANSWER

Let a be a vector with direction ratios 2,3,−6.

⇒   a=2i^+3j^−6k^

Let b be a vector with direction ratios 3,−4,5.

⇒  b=3i^−4j^+5k^

Let θ be the angle between the given vectors.

Now,

⇒  cosθ=∣a∣∣b∣a.b

                

                =∣2i^+3j^−6k^∣∣3i^−4j^+5k^∣(2i^+3j^−6k^).(3i^−4j^+5k^)