find the angle between vectors a and b if a.b=a×b
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Answered by
113
since the magnitude of a.b and a×b are equal,
abcosθ=absinθ,
cosθ=sinθ
tanθ=1
θ=45°,225°
abcosθ=absinθ,
cosθ=sinθ
tanθ=1
θ=45°,225°
Mmvikas:
its ABsin (theta)n^
where n^ goes
plzz reply fast
cross product is vector ,dot product is scalar
The only way they can be equal is when you're talking about the magnitude only
Thus the ň,is removed as it represents the direction of the vector
Answered by
43
The angle between vectors a and b if a.b=a×b:
Substitute in the given equation we get AB Sin(x) = AB Cos(x),
Now Sin(x)= Cos(x).
Finally we get Tan(x)= 1.
Since the magnitude of a.b and a×b are equal,
abcosθ=absinθ,
cosθ=sinθ,
tanθ=1 and θ=45°, 225.
That is x= 45° so your answer will be 1.
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