Find the angle between vectors A=i-2j-3k. B=-i+j-2k
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An easier way to find the angle between two vectors is the dot product formula(A.B=|A|x|B|xcos(X)) let vector A be 2i and vector be 3i+4j. As per your question, X is the angle between vectors so: A.B = |A|x|B|x cos(X) = 2i.
Explanation:
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