Question

`find the angle between vectors a= i + j with x-axis.`..​

Answer 1

Answer:

A=i+j

let the x-axis vector be X

and X=i

as from vectors concept cosθ =A.B/|A||B|        [A.B= scalar product of vectors]

now,

cosθ=(i+j).(i)/(√2)(1)                                              [|A|=√1²+1²=√2 ,|x|=√1²=1]

cosθ=1/√2                                                           [(i+j).(i)=1]

θ=45⁰