Question

Find the angle between vectors when maginitude of vectors is root 3 and 2 also a.b =root6

Answer 1

Explanation:

cos theta=a.b/|a||b|

=√6/√3*2

=√6/2√3

=√3*2/2√3

=√2/2

=√2/2*√2/√2....... (RATIONALIZING)

=2/2√2

=1/√2

so, cos theta=1/√2

so, theta=45°

therefore the angle between vectors is 45°.

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