Find the angle between vectors when maginitude of vectors is root 3 and 2 also a.b =root6
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Explanation:
cos theta=a.b/|a||b|
=√6/√3*2
=√6/2√3
=√3*2/2√3
=√2/2
=√2/2*√2/√2....... (RATIONALIZING)
=2/2√2
=1/√2
so, cos theta=1/√2
so, theta=45°
therefore the angle between vectors is 45°.
Hope it will help you.
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