Question

find the angle between y=x^2 and y=(x-3)^2​

Answer 1

Answer:

Step-by-step explanation:al seel Abadan shill artful SDL

Answer 2

Answer:

y=x^2 - (1)

y=(x-2)^2 - (2)

Using (2) in (1),

(x-2)^2=x^2

= x^2+4-4x=x^2

= 4x = 4

x = 1

= y = 1

Therefore the point of intersecting is (1,1)

y = x^2 (1,1)

Differentiate with respect to x

dy/dx = 2x

slope of tongent

m = (dy/dx) (1,1)

= 2 (1) = 2.