Question

Find the angle between y=x² and y=(x-3)²​

Answer 1

Answer:

here is the answer for your question

Answer 2

Answer:

The correct answer is the tan inverse (3/4)

Step-by-step explanation:

Given: y=x²............(1) and y=(x-3)²​ ...........(2)

To find: angle between points

we know that,

y=(x-3)²​

x2=x2 + 9 - 6x

x2 - x2 = 9 - 6x

6x= 9,   x=3/2

put the value of x in y then we get,

y= 9/4

we get two points that are, x=3/2 and y=9/4

take derivative of 1 and 2

y= x2

dy/dx = 2x = m1,     m1=3/2 x 2=3

Now, similiarly, m2= -3

using formula, tan theta = |m1-m2/ 1+m1m2|

=|3-(-3)/1-9|

=|-6/8|

=3/4

theta= tan inverse (3/4)