Find the angle betwenn the vector A= 2i -3j+5k and the x, y,and z axes, respectively.
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But if you look at the components of the vector (x = –20 miles, y = –20 miles), they’re both negative, so the angle must be between -90 degrees and -180 degrees. If you subtract 180 degrees from your answer of 45 degrees, you get –135 degrees, which is your actual angle measured from the positive x-axis in the clockwise direction.
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