find the angle btw i+j+k and i
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Answer:
arccos (1/√3).
Explanation:
We want to determine the angle between the vector i+j+k and the i which is X axis.
We can use the dot product to get this value.
The vector i is a unit vector along the X axis.
⇒ The angle between the vector i+j+k and the X axis is the same as the angle between the vector i+j+k and the vector i.
Let the angle between these two vectors by θ.
Taking the dot product of these two vectors, we get,
(i+j+k)⋅i = | i+j+k | | i |cosθ.
⇒1 =√3 ⋅1 ⋅cosθ ⇒ cosθ = 1/√3
⇒ θ = arccos (1/√3).
⇒ The angle between the vector i+j+k and the i or X axis is arccos (1/√3). (Answer)
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