Question

find the angle described by the line x-y=0 to the x-axis

Answer 1

Here x - y = 0 => x = y or y = x

=> if we draw a graph of y = x ---( i ), we get a straight line passing through the origin...

Now We also know that , y = mx + c ----( ii )
where
m = slope of a line
c = y intercept ( where line cuts y - axis )
if we compare the equation ( i ) and ( ii ) , we get
y = 1 × x + 0
y = m × x + c
m = 1 and c = 0
Here m = 1 , where m is a slope of a line
m = tan @
where @ = angle between the line and X-axis

=> tan @ = 1
=> tan @ = tan 45° ( since tan 45° = 1 )
=> @ = 45°

Thus angle betwenn the line ( i ) and X- axis is 45°

Answer 2

Step-by-step explanation:

2,3,4,5,6,7,8,9,0,1