Question

find the angle Guyz..

Answer 1

b....................

Answer 2

In the above question,
Angle APQ=58°
Angle in semicircle is 90° i.e. angle QPR=90°
by linear pair property, angle BPR=180-(90+58)=32°
CONSTRUCTION:Draw OP.
in triangle OPB, angle OPB=90° (angle by tangent)
angle OPD=angle OPR + angle BPR
90°=angle OPR+32°
angle OPR=58°
in triangle OPR
OP=OR. (radius)
so, angle OPR=angle ORP=58°
in triangle QPR
by angle sum property,
angle PQB +angle QPR +angle PRQ=180°
angle PQB=90°+58°=180°
angle PQB=180-(90+58)=32°
answer is 32°