Question

find the angle if three times its supplement is 60 degree more than 6 time its complement​

Answer 1

Answer:

$Let \: the \: angle \: be \: x$

$ATQ,$

$3(180-x)=60+6(90-x)$

$540-3x=60+540-6x$

$6x-3x=600-540$

$3x=60$

$x=20^\:o$