Math, asked by SAHILKHAN0721, 5 months ago

Find the angle made by the line joining (4,3) and (-2,-3) with the positive direction of X-axis​

Answers

Answered by singhprem231
0

Answer:

Although the solution is smaller, I am giving a proper explanation of the process. For the shorter solution dive down to the end of the answer.

Let us first find the line joining (5, 3) and (-1, -3). The general form of the line is:

y=mx+cy=mx+c , where m is the slope and c is a constant.

The slope is defined as:

m=(y1−y2)/(x1−x2)m=(y1−y2)/(x1−x2) ……. (1)

Here (x1, y1) = (5, 3) and (x2, y2) = (-1, -3)

Substituting the values in the equation (1), we get

m = (3-(-3)) / (5-(-1)) = (3+3) / (5 + 1)

=> m = 6/6 = 1

Hence m = 1, which gives us the equation of the line as:

y=1.x+cy=1.x+c

y = x + c

To get the value of the constant c, we can use either of the given points

lets take (5, 3) for simplicity,

=> 5=3+c5=3+c

=> c=−2c=−2

So the equation of the line is: y = x -2.

The line meets the x-axis at y=0, putting this value in the equation of the line,

we get x = 2.

i.e. (2, 0) is a point on the line.

Now we get a right-angled triangle ABC between three points A(2, 0) , B(5, 3) and C(5, 0).

Using this triangle we shall find the angle between the line and the positive x-axis.

Our line is AB, and x-axis is AC. BC is perpendicular to x-axis. The want to find the angle between AB and AC, let it be p.

Since it is a right-angled triangle, we can say that:

tanp=height/base=BC/ACtanp=height/base=BC/AC

=>tanp=3/3=1=>tanp=3/3=1

=>tanp=tan45deg=>tanp=tan45deg

=>p=45deg=>p=45deg

Hence the angle is 45deg. our answer.

Short Solution: if you analyse closely, BC/AC is nothing but the slope m.

Hence, tanp=mtanp=m

=>p=arctanm=>p=arctanm

=>p=arctan1=45deg=>p=arctan1=45deg , our answer.

p=45degp=45deg

Thank you for reading.

For better understanding of the concepts:

How use the slope formula and find the slope of a line, whether the Slope is positive, negative or undefined.

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