Question

find the angle of deviation if the angle of incidence is 40degree and angle of emergent is 50 degree
find the angle of deviation when the angle of incidence is equals to 15 degree and the angle of emergent is equals to 40 degree ​

Answer 1

Answer:

→ PART 1.....

★ Angle of Incidence = 40°

★ Angle of Emergence = 50°

★ A ( Refractive angle of prism ) = 60° for equilateral....

★ DELTA = Angle of deviation

$delta = i + e - a$

★ Delta = 40 + 50 - 60 ≈ 30°

-------BUT ORIGINALLY--------

it is ;

$\leqslant 30$

«« REASON »»

Due to TIR ; IT GETS MORE ABSORBED AND.... DUE TO THIS... THE.. REFRACTED RAY MAKES LESSER DEVIATION.....

###### PART 2 ####

★ Angle of Incidence = 15°

★ Angle of Emergence = 40°

++++ Using the previous formula of

" Deviation " :::::

»» Delta = 15 + 40 - 60 = -5°

»» It is " NEGATIVE " because... The emergent Ray suffers .... deviation but towards... NORMAL.....so it's negative...

TQ ❤ ❤