Question

find the angle of elevation of a point to the top of a tower if it is at a distance of root 3 ​

Answer 1

Answer:

Let BD be the height of the tower and AE be the distance of the eye level of the observer from the ground level.

Draw EC parallel to AB such that AB=EC.

Given AB=EC=30

3

m and AE=BC=1.5m

In right angled △DEC,

tan30

∘

=

EC

CD

⇒CD=ECtan30

∘

=

3

30

3

∴CD=30m

Thus, the height of the tower, BD=BC+CD

=1.5+30=31.5m.

hope my answer helps u please follow me and mark me as Brainliest...