find the angle of elevation of a point which is at a distance of 30m from base of a tower 10√3m high
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let , Angle of elevation = θ⁰
base, b=30m
height of tower,h=10√3m
Tan θ = h/b
Tanθ=10√3/10
Tanθ=√3
Tanθ=Tan60⁰
θ=60⁰ or π/3 radians
base, b=30m
height of tower,h=10√3m
Tan θ = h/b
Tanθ=10√3/10
Tanθ=√3
Tanθ=Tan60⁰
θ=60⁰ or π/3 radians
GauravGumber:
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