find the angle of elevation of the sun if the length of the shadow of the tower of height 20 m is 20√3
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Step-by-step explanation:
Let AB be the tower of height 300 ft.
Let BC be the length of the shadow of the tower such that ∠ACB=30
o
Now,
tan30=
BC
AB
⇒
3
1
=
BC
300
⇒BC=300
3
ft
So, length of the shadow of the tower is 300
3
ft
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