Question

Find the angle of elevation of the sun if the length of the shadow of a tower of height 20m is

20 3m​

Answer 1

Answer:

Given tower AB is 20 m and BC shadow on the ground is 203

Then tanθ=

BC/AB= 203/20= 31 =tan30°

Let the distance AC=x

Then sin30°

= AC\AB = x20 =>21 = x20⇒x=40m

Then distance AC is 40 m