Question

Find the angle of elevation of the sun when the shadow of a pole 6m high 2√3 m long​

Answer 1

Answer:

Sun's angle of elevation = 60°

Step-by-step explanation:

Given:

• Height of pole = AB = 6 m
• Length of shadow = BC = 2√3 m

To find:

∠ACB = Sun's elevation = θ

Solution:

In the given figure,

tan θ = AB/BC

→ tan θ = 6 ÷ 2√3

→ tan θ = 3 ÷ √3

→ tan θ = (√3 × √3) ÷ √3

→ tan θ = √3

→ tan θ = tan 60°

∴ θ = 60°

KNOW MORE:

• tan 30° = 1/√3
• tan θ is defined as the opposite side divided by Hypotenuse.
• sin θ is defined as the opposite side divided by Hypotenuse.
• cos θ is defined as the adjacent side divided by Hypotenuse.