Math, asked by SIBI1712, 10 months ago

Find the angle of elevation of the top of a tower from a point on the ground, which is 30 m

away from the foot of a tower of height 10
 \sqrt{3}
m.​

Answers

Answered by BrainlyConqueror0901
19

\blue{\bold{\underline{\underline{Answer:}}}}

\green{\tt{\therefore{Angle\:of\:elevation=30\degree}}}

\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}

 \green{\underline \bold{Given:}} \\  \tt:  \implies Height \: of \: tower = 10 \sqrt{3}  \: m \\  \\  \tt:  \implies Distance \: between  \: foot \: of \: the \: tower  = 30 \: m \\  \\  \red{\underline \bold{To \: Find:}}\\  \tt:  \implies Angle \: of \: elevation = ?

• According to given question :

 \tt \circ \: Let \: angle \: of \: elevation \: be \:  \theta \\  \\  \bold{As \: we \: know \: that} \\  \tt:  \implies tan \:  \theta =  \frac{perpendicular}{base}  \\  \\ \tt:  \implies tan \:  \theta =  \frac{10 \sqrt{3} }{30}  \\  \\ \tt:  \implies tan \:  \theta =   \frac{ \sqrt{3} }{3}  \\  \\ \tt:  \implies tan \:  \theta =   \frac{1}{ \sqrt{3} }  \\  \\ \tt:  \implies tan \:  \theta = tan \: 30 \degree \\  \\  \green{\tt:  \implies  \theta =  30 \degree}\\\\ \green{\tt\therefore Angle\:of\:elevation\:from\:top\:of\:tower\:to\:ground\:is\:30\degree}

Answered by Saby123
18

 \tt{\huge{\orange { Hello!!! }}} B.Q

QUESTION :

Find the angle of elevation of the top of a tower from a point on the ground, which is 30 m

Find the angle of elevation of the top of a tower from a point on the ground, which is 30 maway from the foot of a tower of height 10

Find the angle of elevation of the top of a tower from a point on the ground, which is 30 maway from the foot of a tower of height 10  \sqrt{3}

Find the angle of elevation of the top of a tower from a point on the ground, which is 30 maway from the foot of a tower of height 10  \sqrt{3} m.

SOLUTION :

This question can be easily solved by using Trigonometric Identities.

Here, the following information is given :

The height of the tower is 10 3m.

The base of the tower is 30 m.

Let the angle of elevation be X °

We know that :

Tan X = Perpendicular / Base

=> 10 3 / 30

=> 3 / 3

=> 3 / 3 ÷ 3 / 3

=> 1 / 3

Tan X = 1 / 3

X = tan ^ -1 ( 1 / 3 )

=> X = 30 °

Hence the angle of elevation is 30°>>>>[ A ]

ADDITIONAL INFORMATION :

Sin => Perpendicular / Hypotenuse

Cos => Base / Hypotenuse

Cot => Base / Perpendicular

Cosec => Hypotenuse / Perpendicular

Sec => Hypotenuse / Base

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