Find the angle of elevation of the top of a tower from a point on the ground, which is 30m away from the foot of a tower of height 10√3 m.
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Answer:
the height of tower is equal to 30×3 =90
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If the observer moves towards the perpendicular line(Tower/ building) then angle of elevation increases and if the observer move away from the perpendicular line(Tower/ building) angle of elevation decreases. Hence, the the angle of elevation is 30°.
thank you
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