Question

Find the angle of elevation of the top of a tower of height 100 root3 from a point ata distance of 100 metres from the foot of the tower on the horizontal plane.

Answer 1

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Answer 2

SOLUTION ☺️

Height of the tower = BC = 100√3m

AB= 100m

Let theta be the required angle of elevation then from figure

=) tan theta = BC/AB

=) 100√3/100

=) √3

Theta = 60°

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